V(x)=0.05x^2-0.51x^2+1.81x+13.35

Solution for V(x)=0.05x^2-0.51x^2+1.81x+13.35 equation:

(V)=0.05V^2-0.51V^2+1.81V+13.35

We move all terms to the left:

(V)-(0.05V^2-0.51V^2+1.81V+13.35)=0

We get rid of parentheses

-0.05V^2+0.51V^2-1.81V+V-13.35=0

We add all the numbers together, and all the variables

0.46V^2-0.81V-13.35=0

a = 0.46; b = -0.81; c = -13.35;
Δ = b2-4ac
Δ = -0.812-4·0.46·(-13.35)
Δ = 25.2201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.81)-\sqrt{25.2201}}{2*0.46}=\frac{0.81-\sqrt{25.2201}}{0.92}
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.81)+\sqrt{25.2201}}{2*0.46}=\frac{0.81+\sqrt{25.2201}}{0.92}
$